How To Create A Loop For This Dropdown Menu?

And, would a loop be more efficient then listing them out one by one? Solution 1: If it's not more efficient, it's certainly more readable and reusable, which is far more important. <select name="birthdayYear" > <option value="0000">Year:</option> <?php for(var $x = year(); $x >= 1900; $x--) { var $selected = ""; if($x == $birthdayYear) { $selected = " selected = 'selected'"; } echo("<option value="$x"$selected>$x</option>"); } ?> </select> Copy In short, my hair is a bird. Solution 2: Basically, you will : Deal with the 0000 specific line yourself, and then, have a for() loop from 2011 to 1900 The loop could look a bit like this : for ($year=2011 ; $year>=1900 ; $year--) { echo '<option value="' . $year . '"'; if ($year == $birthdayYear) { echo 'selected="selected"'; } echo '>' . $year . '</option>' . PHP_EOL; } Copy Of course, the 2011 year should probably not be hard-coded -- take a look at date() for a possible way of getting the current year. Solution 3: <select name="birthdayYear" > <option value="0000"<?php echo $birthdayYear == '0000' ? 'selected="selected"' : ''; ?>>Year:</option> <?php for($i=date('Y'); $i>1899; $i--) { $selected = ''; if ($birthdayYear == $i) $selected = ' selected="selected"'; print('<option value="'.$i.'"'.$selected.'>'.$i.'</option>'."\n"); } ?> </select> Copy And, would a loop be more efficient then listing them out one by one? I don't think you have to worry about efficiency. Using a loop just looks cleaner it will be easier to maintain I think. Solution 4: for ($x=(int)date("Y"); $x>=1900; $x=$x--) { echo "<option value=\"", $x, "\"", ($birthdayYear==$x) ? " selected=\"selected\"" : "", ">", $x, "</option>" } Copy This has the added bonus that you don't have to update it every year. Solution 5: Try this: <select name="birthdayYear" > <?php if($year == '0000') { echo '<option value="0000" selected="selected">0000</option>'; } else { echo '<option value="0000">0000</option>'; } for($year = intval(date('Y')); $year > 1900; $year --) { if($year == $birthdayYear) { echo '<option value="'.$year.'" selected="selected">'.$year.'</option>'; } else { echo '<option value="'.$year.'">'.$year.'</option>'; } } ?> </select> Copy Share Post a Comment for "How To Create A Loop For This Dropdown Menu?" Top Question Adding CSS Border Changes Positioning In HTML5 Webpage I'm having a problem with the page elements moving when… Set CSS Width To 100% + Right Border Is Missing? I set a div's width to 100% of the window. When I apply… 2 Side By Side Divs Centered? Well i have 2 divs that i want to be side by side and align… SharePoint 2013 - Display The Detail From A List Item In A Branded Page, NOT The Default SharePoint Details Page I am a COMPLETE beginner when it comes to SharePoint! So, f… Weird Dark Border :after Css Arrow In Firefox In an attempt to make an arrow in pure CSS for my tooltip, … Building A Wysiwyg Editor I need to build a wysiwyg editor for a project I am working… How To Add Vertical Sub-menu To Horizontal Menu Using Css And Html? I want to add a vertical sub-menu to my horizontal menu. I … Zend Html5 Form Element Types Is there any easy way to get HTML5 Form elements into a Zen… What Are The Flaws , One Must Care In File Upload I have a Linux server , i am having an upload image in my w… Html Parsing With Jsoup I am trying to parse the html of the following URL: http://… December 2024 (1) November 2024 (39) October 2024 (60) September 2024 (16) August 2024 (372) July 2024 (341) June 2024 (684) May 2024 (1293) April 2024 (819) March 2024 (1495) February 2024 (1638) January 2024 (1341) December 2023 (1383) November 2023 (417) October 2023 (640) September 2023 (314) August 2023 (341) July 2023 (272) June 2023 (356) May 2023 (185) April 2023 (154) March 2023 (144) February 2023 (181) January 2023 (256) December 2022 (134) November 2022 (215) October 2022 (177) September 2022 (163) August 2022 (294) July 2022 (90) Menu Halaman Statis Beranda © 2022 - Html5 stackoverflow Examples